(12x^3-14x^2-40x)/(2x-5)

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Solution for (12x^3-14x^2-40x)/(2x-5) equation:


D( x )

2*x-5 = 0

2*x-5 = 0

2*x-5 = 0

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

x in (-oo:5/2) U (5/2:+oo)

(12*x^3-(14*x^2)-(40*x))/(2*x-5) = 0

(12*x^3-14*x^2-40*x)/(2*x-5) = 0

12*x^3-14*x^2-40*x = 0

2*x*(6*x^2-7*x-20) = 0

6*x^2-7*x-20 = 0

DELTA = (-7)^2-(-20*4*6)

DELTA = 529

DELTA > 0

x = (529^(1/2)+7)/(2*6) or x = (7-529^(1/2))/(2*6)

x = 5/2 or x = -4/3

2*x*(x+4/3)*(x-5/2) = 0

(2*x*(x+4/3)*(x-5/2))/(2*x-5) = 0

( 2*x )

2*x = 0 // : 2

x = 0

( x+4/3 )

x+4/3 = 0 // - 4/3

x = -4/3

( x-5/2 )

x-5/2 = 0 // + 5/2

x = 5/2

x in { 5/2}

x in { 0, -4/3 }

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